$x = \log_{120}2^9 + \log_{120}3^3 + 2\log_{120^2}125$ $x = \log_{120}(2^3)^3 + \log_{120}3^3 + \log_{120}5^3$ $x = \log_{120}(8^3\cdot 3^3\cdot 5^3) = \log_{120}120^3$ $x = 3\log_{120}120 \therefore \boxed{x = 3}$