$x^3 = x+2$ $\implies$ $(x^3)^3 = (x+2)^3$ $\implies$ $x^9 = x^3 + 6x^2 + 12x + 8$ Temos $x^9$ $=$ $(x+2) + 6x^2 + 12x + 8$ $=$ $6x^2 + 13x + 10 $ $x^{10} = x^9 \cdot x$ $\implies$ $x^{10}$ $=$ $6x^3 + 13x^2 + 10x $ $=$ $6(x+2) + 13x^2 + 10x $ Portanto, $\boxed{x^{10} = 13x^2 + 16x + 12}$ Alternativa $\mathbb{(C)}$