Discriminante é igual a √(b²-4ac) A natureza das raízes é complexa. [5±√(25-72)]/2.3=(5±i√47)/6 X1=(5+i√47)/6 X2=(5-i√47)/6

$3x^2 - 5x + 6 = 0$ $x = \frac{-(-5) \pm \sqrt{(-5^2)-4.3.6}}{2.3}$ $x = \frac{-(-5) \pm \sqrt{25-4.3.6}}{2.3}$ $x = \frac{-(-5) \pm \sqrt{25-12.6}}{2.3}$ $x = \frac{-(-5) \pm \sqrt{25-72}}{2.3}$ $x = \frac{-(-5) \pm \sqrt{-47}}{2.3}$ $x = \frac{-(-5) \pm \sqrt{47i}}{2.3}$ $x = \frac{5 \pm \sqrt{47i}}{2.3}$ $x = \frac{5 \pm \sqrt{47i}}{6}$ $x = \frac{5+\sqrt{47i}}{6}$ $x = \frac{-\sqrt{47i}+5}{6}$