$\int 2\sqrt{2-3x}dx$ $u = 2 -3x$ $du = -3dx$ $dx = \frac{-du}{3}$ Substituindo o valor de $u$ e $dx$ na integral: $\int 2\sqrt{u}(\frac{-du}{3})$ Retirando as constantes da integral: $\frac{-2}{3}\int\sqrt{u}du$ $\int\sqrt{u}du = \frac{2}{3}(u)^\frac{3}{2} + C$ Logo: $\int 2\sqrt{2-3x}dx = \frac{-2}{3}\frac{2}{3}(u)^\frac{3}{2} + C = \frac{-4}{9}(u)^\frac{3}{2} + C $ Substituindo o valor de $u$: $u = 2 -3x$ $\int 2\sqrt{2-3x}dx = \frac{-4}{9}(2 - 3x)^\frac{3}{2} + C $