Dadas as afirmativas abaixo:

1. I) $\sqrt{{\left(-2\right)}^2}=-2$
   

2. II) $\frac{\sqrt{-4}}{\sqrt{-9}}=\frac{\sqrt{\left(-1\right)\left(4\right)}}{\sqrt{\left(-1\right)\left(9\right)}}=\frac{\sqrt{-1}\cdot \sqrt{4}}{\sqrt{-1}\cdot \sqrt{4}}=\frac{\sqrt{4}}{\sqrt{9}}=\frac{2}{3}$
   

3. III) ${\left(\sqrt{-2}\right)}^2=-2$
   

4. IV) $\sqrt{3+2}=\sqrt{3}+\sqrt{2}$
   

Assinale a alternativa correta: