Definimos a função $f:\mathbb{N}\to \mathbb{N}$ da seguinte forma:$$\{\begin{array}{l}f(0)=0\\ f(1)=1\\ f(2n)=f(n),n\ge 1\\ f(2n+1)=f(n)+2^{\lfloor {\log }_{2}n\rfloor },n\ge 1\end{array}$$Determine $f(f(2019))$.