Calcule os valores de $X$ e $Y$ sabendo que: $$X>Y$$ $${\log }_5(X+Y)-2{\log }_{25}5=0$$ $$5^{{\log }_5(X+Y)}+\text{antiln}\left(\frac{{\log }_{3}XY}{{\log }_{3}e}\right)+{\text{colog}}_5(X+Y)-5{\log }_{3}9=0$$