[ITA 2016] Se M=[12−10] e N=[2−113], então...

Se $M = [12 - 1 0]$ e $N = [2 - 1 13]$ , então $M N^{T} - M^{- 1} N$ é igual a

[\frac{3}{2} \frac{5}{2} - \frac{5}{2} - \frac{3}{2}]

[\frac{3}{2} \frac{7}{2} - \frac{1}{2} - \frac{5}{2}]

[\frac{3}{2} \frac{13}{2} - \frac{11}{2} - \frac{5}{2}]

[\frac{3}{2} \frac{13}{2} - \frac{5}{2} - \frac{3}{2}]

[\frac{3}{2} \frac{13}{2} - \frac{11}{2} - \frac{3}{2}]