Seja $a\in \mathbb{R}$ com $a>1$. Se $b={\log }_{2}a$, então o valor de $$lo{g}_4{a}^3+lo{g}_{2}4a+lo{g}_2\frac{a}{a+1}+({\log }_{8}a{)}^2-{\log }_{\frac{1}{2}}\frac{a^2-1}{a-1}$$ é: